Reputation: 195
I'm trying to get the number of days in a current year.
When I try the solution on Number of days in the current month using iPhone SDK?, and replace NSMonthCalendarUnit by NSYearCalendarUnit, I still get the number of days for that month.
Does anyone know how I should do this?
Thanks in advance for your help.
Upvotes: 7
Views: 2976
Reputation: 14935
Here's a super accurate NSCalendar
extension in Swift 2:
extension NSCalendar {
func daysInYear(date: NSDate = NSDate()) -> Int? {
let year = components([NSCalendarUnit.Year], fromDate: date).year
return daysInYear(year)
}
func daysInYear(year: Int) -> Int? {
guard let begin = lastDayOfYear(year - 1), end = lastDayOfYear(year) else { return nil }
return components([NSCalendarUnit.Day], fromDate: begin, toDate: end, options: []).day
}
func lastDayOfYear(year: Int) -> NSDate? {
let components = NSDateComponents()
components.year = year
guard let years = dateFromComponents(components) else { return nil }
components.month = rangeOfUnit(NSCalendarUnit.Month, inUnit: NSCalendarUnit.Year, forDate: years).length
guard let months = dateFromComponents(components) else { return nil }
components.day = rangeOfUnit(NSCalendarUnit.Day, inUnit: NSCalendarUnit.Month, forDate: months).length
return dateFromComponents(components)
}
}
You can use it like this:
let calendar = NSCalendar.currentCalendar() // I'm using the Gregorian calendar
calendar.daysInYear() // 365 (since it's currently 2015)
calendar.daysInYear(2016) // 366 (leap year!)
This is super flexible since we don't assume anything about the length of the calendar:
let hebrew = NSCalendar(calendarIdentifier: NSCalendarIdentifierHebrew)
hebrew?.daysInYear(-7) // 354
hebrew?.daysInYear(-100) // 384
Enjoy.
Upvotes: 8
Reputation: 2096
As example:
func daysInYear(year: Int) -> Int {
var calendar = NSCalendar(calendarIdentifier: NSGregorianCalendar)
var b = NSDate.dateWithNaturalLanguageString("01.01.\(year)", locale: NSLocale.currentLocale()) as! NSDate
var e = NSDate.dateWithNaturalLanguageString("12.31.\(year)", locale: NSLocale.currentLocale()) as! NSDate
return calendar!.components(NSCalendarUnit.CalendarUnitDay, fromDate: b, toDate: e, options: nil).day + 1
}
But default days return 355 and 354 this caused (may be) that counting begin from zero :)
Upvotes: 0
Reputation: 32507
Use the NSCalendar
and NSDateComponent
classes, like this:
long GetDaysInYear(int year) {
NSDateComponents* c = [[NSDateComponents alloc] init];
c.year = year;
NSCalendar* cal = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDate* startDate = [cal dateFromComponents:c];
c.year += 1;
NSDate* endDate = [cal dateFromComponents:c];
return [cal components:NSDayCalendarUnit fromDate:startDate toDate:endDate options:0].day;
}
Upvotes: 1
Reputation: 1813
I finally came up with a solution that works. What I do is first calculate the number of months in the year and then for each month calculate the number of days for that month.
The code looks like this:
NSUInteger days = 0;
NSCalendar *calendar = [NSCalendar currentCalendar];
NSDate *today = [NSDate date];
NSDateComponents *components = [calendar components:NSYearCalendarUnit fromDate:today];
NSUInteger months = [calendar rangeOfUnit:NSMonthCalendarUnit
inUnit:NSYearCalendarUnit
forDate:today].length;
for (int i = 1; i <= months; i++) {
components.month = i;
NSDate *month = [calendar dateFromComponents:components];
days += [calendar rangeOfUnit:NSDayCalendarUnit
inUnit:NSMonthCalendarUnit
forDate:month].length;
}
return days;
It is not as neat as I would have hoped for but it will work for any calendar such as the ordinary gregorian one or the islamic one.
Upvotes: 5
Reputation: 49364
If you're only going to use the Gregorian Calender, you can calculate it manually.
http://en.wikipedia.org/wiki/Leap_year#Algorithm
if year modulo 400 is 0 then leap
else if year modulo 100 is 0 then no_leap
else if year modulo 4 is 0 then leap
else no_leap
Upvotes: 5