Reputation: 1236
I have a view created using Bake that has the following:
<fieldset>
<legend><?php echo __('Edit Device'); ?></legend>
<?php
echo $this->Form->input('DeviceID');
echo $this->Form->input('DeviceTypeID');
echo $this->Form->input('UserID');
echo $this->Form->input('Type');
echo $this->Form->input('KeyPadID');
echo $this->Form->input('Version');
echo $this->Form->input('Description');
echo $this->Form->input('UpdateID');
?>
</fieldset>
Which saves to the table:
CREATE TABLE `device` (
`DeviceID` VARCHAR(255) NOT NULL ,
`DeviceTypeID` INT(11) NOT NULL ,
`UserID` INT(10) NOT NULL ,
`Type` VARCHAR(10) NULL DEFAULT NULL ,
`KeyPadID` INT(10) NULL DEFAULT NULL ,
`Version` VARCHAR(255) NULL DEFAULT NULL ,
`Description` TINYBLOB NULL ,
`UpdateID` INT(11) NULL DEFAULT NULL ,
PRIMARY KEY (`DeviceID`),
INDEX `FK_USER` (`UserID`),
INDEX `FK_devices_updates` (`UpdateID`),
INDEX `FK_device_devicetype` (`DeviceTypeID`),
CONSTRAINT `FK_device_devicetype` FOREIGN KEY (`DeviceTypeID`) REFERENCES `devicetype` (`DeviceTypeID`),
CONSTRAINT `FK_devices_updates` FOREIGN KEY (`UpdateID`) REFERENCES `update` (`ID`) ON UPDATE CASCADE ON DELETE CASCADE,
CONSTRAINT `FK_USER` FOREIGN KEY (`UserID`) REFERENCES `user` (`UserID`) ON UPDATE CASCADE ON DELETE CASCADE
)
My problem is that when the form is displayed, it shows DeviceTypeID and UserID as well as UpdateID as the foreign key value instead of a drop down with the caption being the text and the value being the ID column. How would I go about setting a field from the foreign table to be the display field and the id as being the value?
Upvotes: 0
Views: 989
Reputation: 335
Update 11-02-2013
First of all I strongly suggest to convert your primary and foreign keys accordingly so that they meet the CakePHP naming conventions.
This means that:
DeviceID
should be id
.DeviceTypeID
should be device_type_id
UserID
should be user_id
Also all primary keys in your tables should be named as id
.
This way you will never have to worry about anything, concerning your models etc.
After that, all your tables must be in plural form. This means that device
table should be devices
, so you should rename it also.
I assume that you also have the following tables: devices_types
and users
.
At this point, I should notice that I would prefer to have a table named devicetype
. I avoid underscored names, because it's very easy to make mistakes using the correct form for each object, class etc. So I don't have to worry whether I should use the CamelCase or not.
Anyway
Your Device
model should be something like that:
<?php
/** Device.php **/
class Device extends AppModel {
public $name = 'Device';
public $belongsTo = array(
'DeviceType' => array(
'className' => 'DeviceType',
'foreignKey' => 'device_type_id'
/** Specify other keys that meet your needs **/
),
'User' => array(
'className' => 'User',
'foreignKey' => 'user_id'
)
);
};
?>
Also your DeviceType
model should be similar to
<?php
/** DeviceType.php **/
class DeviceType extends AppModel {
public $name = 'DeviceType';
};
In your edit()
method, you should query your DeviceType
in something like this:
...
$devicetypes = $this->Device->DeviceType->find('list', array('id', 'caption'));
$this->set(compact('devicetypes'));
...
This way in your view the respective form element sets the <select>
menu correctly.
PS: You should follow the CakePHP conventions about model-naming etc... Mine was just an example.
Upvotes: 2