CODEWITHSUNDEEP
javaparsing
domen
domen

Reputation: 1279

Invalid int when converting from string to integer

I'm trying to convert a string that contains just numbers to integer using int number = Integer.parseInt(string), but it returns #

error: Invalid int: "number"

For example, if the string is "10", it returns: Invalid int: "10". What is wrong?

Edit:

FileInputStream fis;
        int number =0;
        String line="";
        try
        {
            fis = new FileInputStream(getFilesDir()+pathToFile);
            BufferedReader reader = new BufferedReader(new InputStreamReader(fis));
            line=reader.readLine();
            Log.e("Read Line", "Read line: *" +line+ "*"); //returns *10*
            try
            {
                number = Integer.parseInt(line.trim());
            }
            catch(NumberFormatException nfe)
            {
                Log.e("ERROR CONVERTING", nfe.getMessage()); // return above error
            }
            reader.close();

        }
        catch(Exception ex)
        {
            Log.e("ERROR OPENING FILE", "Can't open file: "+ex.getMessage());
        }

Upvotes: 1

Views: 6257

Answers (3)

Charleston
Charleston

Reputation: 1569

Some times it means "the number is too big".

I come across a situation where it happens because my number was too big. Example:

Integer.parseInt("201506121234567");

It causes me the exception NumberFormat.

To solve, I changed to this:

Long.parseLong("201506121234567");

Hope it helps someone!

Upvotes: 2

domen
domen

Reputation: 1279

I used the code in the answer from this question: LINK

str = str.replaceAll("\\D+","");

Don't know why it doesn't work without this, because there are no other characters besides numbers in the string, but not it works.

Upvotes: 4

Fritz
Fritz

Reputation: 10045

Did you actually try with "10" or any other number? The error is pretty specific.

Invalid int: "number"

This means that in this line

Integer.parseInt(string)

string has the value "number". Check where are you setting this value and verify that you're actually setting a numeric string.

Upvotes: 1

Related Questions