CODEWITHSUNDEEP
phpstring
nooblag
nooblag

Reputation: 349

Extract top domain from string php

I need to extract the domain name out of a string which could be anything. Such as: 

$sitelink="http://www.somewebsite.com/product/3749875/info/overview.html";

or

$sitelink="http://subdomain.somewebsite.com/blah/blah/whatever.php";

In any case, I'm looking to extract the 'somewebsite.com' portion (which could be anything), and discard the rest.

Upvotes: 13

Views: 20444

Answers (6)

eldadfux
eldadfux

Reputation: 198

You can use the Utopia Domains library (https://github.com/utopia-php/domains), it will return the domain TLD and public suffix based on Mozilla public suffix list (https://publicsuffix.org), it can be used as an alternative to the currently archived TLDExtract package.

You can use 'parse_url' function to get the hostname from your URL and than use Utopia Domains parser to get the correct TLD and join it together with the domain name:

<?php

require_once './vendor/autoload.php';

use Utopia\Domains\Domain;

$url = 'http://demo.example.co.uk/site';

$domain = new Domain(parse_url($url, PHP_URL_HOST)); // demo.example.co.uk

var_dump($domain->get()); // demo.example.co.uk
var_dump($domain->getTLD()); // uk
var_dump($domain->getSuffix()); // co.uk
var_dump($domain->getName()); // example
var_dump($domain->getSub()); // demo
var_dump($domain->isKnown()); // true
var_dump($domain->isICANN()); // true
var_dump($domain->isPrivate()); // false
var_dump($domain->isTest()); // false

var_dump($domain->getName().'.'.$domain->getSuffix()); // example.co.uk

Upvotes: 0

user3251285
user3251285

Reputation: 163

2 complexe url

$url="https://www.example.co.uk/page/section/younameit";
or
$url="https://example.co.uk/page/section/younameit";

To get "www.example.co.uk":

$host=parse_url($url, PHP_URL_HOST);

To get "example.co.uk" only

$parts = explode('www.',$host);
$domain = $parts[1];

// ...or...

$domain = ltrim($host, 'www.')

If your url includes "www." or not you get the same end result, i.e. "example.co.uk"

Voilà!

Upvotes: 4

Rafa
Rafa

Reputation: 891

For a string that could be anything, new approach:

function extract_plain_domain($text) {

    $text=trim($text,"/");
    $text=strtolower($text);

    $parts=explode("/",$text);
    if (substr_count($parts[0],"http")) {
        $parts[0]="";
    }
    reset ($parts);while (list ($key, $val) = each ($parts)) {
            if (!empty($val)) { $text=$val; break; }
    }

    $parts=explode(".",$text);
    if (empty($parts[2])) {
        return $parts[0].".".$parts[1];
        } else {
        $num_parts=count($parts);
        return $parts[$num_parts-2].".".$parts[$num_parts-1];
        }

} // end function extract_plain_domain

Upvotes: 0

Oleksandr Fediashov
Oleksandr Fediashov

Reputation: 4335

You need package that uses Public Suffix List, only in this way you can correctly extract domains with two-, third-level TLDs (co.uk, a.bg, b.bg, etc.) and multilevel subdomains. Regex, parse_url() or string functions will never produce absolutely correct result.

I recomend use TLD Extract. Here example of code:

$extract = new LayerShifter\TLDExtract\Extract();

$result = $extract->parse('http://www.somewebsite.com/product/3749875/info/overview.html');
$result->getSubdomain(); // will return (string) 'www'
$result->getHostname(); // will return (string) 'somewebsite'
$result->getSuffix(); // will return (string) 'com'
$result->getRegistrableDomain(); // will return (string) 'somewebsite.com'

Upvotes: 2

user652649
user652649

Reputation:

here it is

<?php

$sitelink="http://www.somewebsite.com/product/3749875/info/overview.html";

$domain_pieces = explode(".", parse_url($sitelink, PHP_URL_HOST));

$l = sizeof($domain_pieces);

$secondleveldomain = $domain_pieces[$l-2] . "." . $domain_pieces[$l-1];

echo $secondleveldomain;

note that this is not probably the behavior you are looking for, because, for hosts like

stackoverflow.co.uk

it will echo "co.uk"

see:

http://publicsuffix.org/learn/

http://www.dkim-reputation.org/regdom-libs/

http://www.dkim-reputation.org/regdom-lib-downloads/ <-- downloads here, php included

Upvotes: 5

Lawrence Cherone
Lawrence Cherone

Reputation: 46602

With parse_url($url)

<?php
$url = 'http://username:password@hostname/path?arg=value#anchor';

print_r(parse_url($url));
?>

The above example will output:

Array
(
    [scheme] => http
    [host] => hostname
    [user] => username
    [pass] => password
    [path] => /path
    [query] => arg=value
    [fragment] => anchor
)

Using thos values

echo parse_url($url, PHP_URL_HOST); //hostname

or

$url_info = parse_url($url);
echo $url_info['host'];//hostname

Upvotes: 26

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