CODEWITHSUNDEEP
phpimagemagick
drewm
drewm

Reputation: 1988

Why would a loaded PHP extension fail on class instantiation?

I have some code which is resizing images, using either Imagick or GD, depending what's available on the server.

I'm testing for availability of each using the extension_loaded() function.

if (extension_loaded('imagick')) {
    $image = new Imagick();
    ...
}

I have one user reporting that they are receiving:

Fatal error: Class 'Imagick' not found

What circumstances would result in the Imagick extension being loaded but the class not available? How should I be testing to make my code more robust?

Upvotes: 3

Views: 873

Answers (4)

PHP Bugs
PHP Bugs

Reputation: 1183

    yum install ImageMagick
    yum install ImageMagick-devel
    pecl install imagick
    echo "extension=imagick.so" > /etc/php.d/imagick.ini
    service httpd restart [/etc/init.d/httpd restart]
    php -m | grep imagick

Reference

Upvotes: 0

Scotty
Scotty

Reputation:

Case sensitive?

'imagick' and Imagick.

Upvotes: 0

Quamis
Quamis

Reputation: 11077

1: always do the checks in a case-insensitive manner (make the string lowercase before comparing it)

2: don't check for the library, check for features. Maybe it has a library version that's buggy or has other function names

3: in php.ini you may disable some functions explicitly by name so I think you should resort to point #2 and check with function_exists instead of extension_*

Also, take a look at /var/log/apache2/errors or the equivalent on that client's server to check for any internal error generated by the ImageMagick extension (segmentation fault or other types of low-level errors should get reported in there...)

Upvotes: 2

Danny Croft
Danny Croft

Reputation: 223

You could check if the class exists also?

class_exists("Imagick")

Upvotes: 2

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