CODEWITHSUNDEEP
android
tez
tez

Reputation: 5300

two views with same id

How does android use R.id.id_name to find views after inflating the XML?

1.Suppose I have two XML's with one button each with same id.

2.I have inflated them and converted them into views

3.In R.id class only one int will be created for both the buttons.

How does android differentiate these buttons with same id Using same Resource name(R.id.id_name) .

Upvotes: 36

Views: 24615

Answers (3)

salezica
salezica

Reputation: 76929

Android takes the easy road: IDs are not application-wide unique, but layout-wide unique.

The value of R.id.foo is the same across two different layouts holding a control with foo id. Since they are not competing for uniqueness, it doesn't matter.

Upvotes: 23

Rob Pridham
Rob Pridham

Reputation: 4928

The ID is not a unique reference.

However, in practice, you differentiate by using the parent view.

If we consider that 'this' is an Activity, set up with a layout that contains your buttons, then:

Button button = (Button) this.findViewById( R.id.id_name );

will return the first one it finds in the layout (I think - not sure the actual behaviour is defined).

However what you might do is call findViewById on some parent view that contains only one such instance with that ID.

LinearLayout okParent = (LinearLayout) this.findViewById( R.id.okLayout );
LinearLayout cancelParent = (LinearLayout) this.findViewById( R.id.cancelLayout );

Button okButton = (Button) okParent.findViewById( R.id.id_name );
Button cancelButton = (Button) cancelParent.findViewById( R.id.id_name );

Conceptually, this is a sort of path based lookup. You should be careful to design your layouts such that this is possible.

Upvotes: 45

Piotr Chojnacki
Piotr Chojnacki

Reputation: 6857

It knows which View should it use, because it looks for View with this specific id in a XML file that is currently set as content view (or is inflated).

Upvotes: 7

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