CODEWITHSUNDEEP
phpimagejpeg
harikrishnan.n0077
harikrishnan.n0077

Reputation: 2057

Error in imagecreatefromjpeg() function in PHP

When using the below php code it shows an error

<?php
$path="/hari002244/album/f41b6b54811c.jpg";
$src = imagecreatefromjpeg($path);
?>

It shows

SCREAM: Error suppression ignored for
Warning: imagecreatefromjpeg(/hari002244/album/f41b6b54811c.jpg): failed to open stream: No such file or directory in C:\wamp\www\newEmptyPHP.php on line 3

But when using

<?php
$path="f41b6b54811c.jpg";
$src = imagecreatefromjpeg($path);
?>

It doesn't show any error.

I had typed the path in URL bar and checked whether file exists.It is working perfectly.

Can you tell me why this error occurs? and also how to overcome this?

Thanks in advance.

Upvotes: 0

Views: 8228

Answers (2)

harikrishnan.n0077
harikrishnan.n0077

Reputation: 2057

Got the answer

Instead of "/hari002244/album/f41b6b54811c.jpg"

Should be used "http://localhost/hari002244/album/f41b6b54811c.jpg"

Upvotes: 1

leftclickben
leftclickben

Reputation: 4614

The first path, "/hari002244/album/f41b6b54811c.jpg" is an absolute path, it starts from the root of the whole file system. Chances are, this path does not exist.

In the second case, it is just a filename "f41b6b54811c.jpg" which is relative to / located in the current working directory, which of course exists.

Upvotes: 4

Related Questions