CODEWITHSUNDEEP
c++sizeofmultidimensional-array
MarJamRob
MarJamRob

Reputation: 3465

Finding the amount of rows and columns for a 2-D array in C++

I know in C++ you can get a arrays amount of rows and columns with:

 int rows = sizeof array / sizeof array[0];
 int cols = sizeof array[0] / sizeof array[0][0];

However is there any better way to do this?

Upvotes: 9

Views: 27256

Answers (2)

ricardo130
ricardo130

Reputation: 165

Also you can use sizeof() function;

int rows =  sizeof (animals) / sizeof (animals[0]);
int cols = sizeof (animals[0]) / sizeof (string);

Example:

#include <iostream>

using namespace std;

void sizeof_multidim_arrays(){
    string animals[][3] = {
        {"fox", "dog", "cat"},
        {"mouse", "squirrel", "parrot"}
    };
    int rows =  sizeof (animals) / sizeof (animals[0]);
    int cols = sizeof (animals[0]) / sizeof (string);
    for(int i = 0; i < rows; i++){
        for(int j = 0; j < cols; j++){
            cout << animals[i][j] << " " << flush;
        }
        cout << endl;    
    }
}

Output:

fox dog cat 
mouse squirrel parrot

Upvotes: 0

Jorge Israel Pe&#241;a
Jorge Israel Pe&#241;a

Reputation: 38576

In C++11 you can do this using template argument deduction. It seems that the extent type_trait already exists for this purpose:

#include <type_traits>
// ...
int rows = std::extent<decltype(array), 0>::value;
int cols = std::extent<decltype(array), 1>::value;

Upvotes: 6

Related Questions