CODEWITHSUNDEEP
javajavascriptjqueryjsonplayframework-2.0
user2054833
user2054833

Reputation: 2165

Play action not responding to json posted

I'm new to play and I am trying to post form data to my Play Action using JQuery. However, I'm getting "expected json" response from Action. I check the HTTP Headers to ensure that the data is being sent and it is so, where am I going wrong and how can I fix it.(Is there a better approach to this)

Script:

$(document).ready (function (){
    $("form").submit (function (e) {
        e.preventDefault();
        $.post("/save",$(this).serialize(),function (data){
            alert(data);
        });
     });
});

Action

public static Result save()
{
    JsonNode json = request().body().asJson();
    if (json == null)
    return ok("expected json");
    else
    {
        String value = json.findPath("video").getTextValue();
        if (value == null)
            return ok("did not find");
        else
            return ok(value) ;
    }
}

routes

  POST   /save                         controllers.Application.save()

Upvotes: 1

Views: 216

Answers (1)

biesior
biesior

Reputation: 55798

Both: Julien Lafont and dfsq are right, first: you are not serializing your form to JSON, second, as Julien stated, you don't need to... Using your current JS you can just use DynamicForm in your save action:

public static Result save() {
    DynamicForm df = form().bindFromRequest();

    String value = df.get("video");
    if (value == null || value.trim().equals(""))
        return badRequest("Video param was not sent");

    // do something with the value

    return ok(value);
}

BTW, don't use ok() for returning responses for wrong requests. You have many options: badRequest(), notFound(), TODO, and wild bunch of other Results, even raw: status(int), so you can read the status in jQuery without passing any additional reasons of fail.

If you really, really need to serialize form to JSON for any reason, let me know, I'll send you a sample.

Upvotes: 2

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