Reputation: 1531
Ok so let's say that I have my object
myobj = {"A":["Abe"], "B":["Bob"]}
and I want to get the first element out of it. As in I want it to return Abe
which has an index of A
. How can I do something along the lines of myobj[0]
and get out "Abe".
Upvotes: 69
Views: 180394
Reputation: 13862
Try:
const obj = {
name: 'John Doe',
age: 34,
country: 'Switzerland',
};
var _key = Object.keys(obj)[0]
var _value = Object.values(obj)[0]
var key = Object.entries(obj)[0][0]
var value = Object.entries(obj)[0][1]
console.log(_key)
console.log(_value)
console.log(key)
console.log(value)
Upvotes: 1
Reputation: 127
$.each(myobj, function(index, value) {
console.log(myobj[index]);
});
Upvotes: 0
Reputation: 149
myobj = {"A":["Abe"], "B":["Bob"]}
Object.keys(myobj)[0]; //return the key name at index 0
Object.values(myobj)[0] //return the key values at index 0
Upvotes: 14
Reputation: 84
var myobj = {"A":["Abe"], "B":["Bob"]};
var keysArray = Object.keys(myobj);
var valuesArray = Object.keys(myobj).map(function(k) {
return String(myobj[k]);
});
var mydata = valuesArray[keysArray.indexOf("A")]; // Abe
Upvotes: 3
Reputation: 1563
I know it's a late answer, but I think this is what OP asked for.
myobj[Object.keys(myobj)[0]];
Upvotes: 117
Reputation: 339836
JS objects have no defined order, they are (by definition) an unsorted set of key-value pairs.
If by "first" you mean "first in lexicographical order", you can however use:
var sortedKeys = Object.keys(myobj).sort();
and then use:
var first = myobj[sortedKeys[0]];
Upvotes: 26
Reputation: 707446
If you want a specific order, then you must use an array, not an object. Objects do not have a defined order.
For example, using an array, you could do this:
var myobj = [{"A":["B"]}, {"B": ["C"]}];
var firstItem = myobj[0];
Then, you can use myobj[0] to get the first object in the array.
Or, depending upon what you're trying to do:
var myobj = [{key: "A", val:["B"]}, {key: "B", val:["C"]}];
var firstKey = myobj[0].key; // "A"
var firstValue = myobj[0].val; // "["B"]
Upvotes: -2