CODEWITHSUNDEEP
iphoneipad
kiran
kiran

Reputation: 4409

how to pass the parameter (void(^)(NSError*))error

How to pass the parameter 

-(void)errorValue:(void(^)(NSError*))error{

[self errMssg];
}

-(void)call{
(void(^)(NSError*))error;

 [self  errorValue ?];
}

Please let me know how to pass (void(^)(NSError*))error to the method!

@All Thanks in Advance

Upvotes: 0

Views: 207

Answers (1)

Matt Wilding
Matt Wilding

Reputation: 20163

You need to properly declare a block variable first. Then you just pass it by name like any other variable:

void(^myBlock)(NSError *) = ^(NSError* error) {
    // Do something
};
[self errorValue:myBlock];

Alternatively, you can pass a block literal directly:

[self errorValue:^(NSError* error) {
    // Do something
}];

Upvotes: 3

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