CODEWITHSUNDEEP
pythondjangodjango-views
Tom
Tom

Reputation: 45114

Can a Django view receive a list as parameter?

I want to submit a form (by POST) that will submit N (unknown) user_id's. Can I make a view receive those ids as a list?

For example

def getids(request,list):

   for id in list:
       usr = User.objects.get(pk=id);
       //do something with it.
       usr.save()

Is 

for id in request.POST['id']:

even possible?

I'm looking for the best accepted way.

Upvotes: 3

Views: 2865

Answers (5)

Matt Kahl
Matt Kahl

Reputation: 823

QueryDict's getlist is what you're looking for.

From the docs:

>>> q = QueryDict('a=1', mutable=True)
>>> q.update({'a': '2'})
>>> q.getlist('a')
['1', '2']

Upvotes: 0

Facundo Casco
Facundo Casco

Reputation: 10585

You can create the form fields with some prefix you could filter later.

Say you use form fields with names like uid-1, uid-2, ... uid-n

Then, when you process the POST you can do:

uids = [POST[x] for x in POST.keys() if x[:3] == 'uid']

That would give you the values of the fields in the POST which start with 'uid' in a list.

Upvotes: 0

Nick Craig-Wood
Nick Craig-Wood

Reputation: 54089

If you are submitting lots of identical forms in one page you might find Formsets to be the thing you want.

You can then make one Form for the userid and then repeat it in a Formset. You can then iterate over the formset to read the results.

Upvotes: 2

c_harm
c_harm

Reputation:

Very close. The POST parameters are actually contained in a QueryDict object in the request.

def getids(request):
    if request.method == 'POST':
        for field in HttpRequest.POST:
            // Logic here

Upvotes: 2

Ionuț G. Stan
Ionuț G. Stan

Reputation: 179139

You should read about QueryDict objects:

>>> q = QueryDict('a=1&a=2&a=3')
>>> q.lists()
[('a', ['1', '2', '3'])]

Upvotes: 5

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