CODEWITHSUNDEEP
androidquery-stringurl-encoding
Pratik
Pratik

Reputation: 30855

How to pass string containing url in query string from android

I need to post string containing url to the server I have able to encoding the url but this will encoding whole string and I need to require only url link to be encoded and decode when get this data back to display in android.

mydomain/post.php?mesg=Hello%2Bhow%2Br%2Bu%250A%2BHttp%253A%252F%252Fwww.google.com%250A%250ATesting%2Burl

Edited

My code

String postStr = "Hello how r u?
                  http://www.google.com"; // suppose user entered string like this way

Uri.Builder builder = new Uri.Builder()
    .scheme("http")
    .authority(domain)
    .path(pageName)
    .appendQueryParameter("mesg", URLEncoder.encode(postStr, "utf-8"))
String urlStr = builder.build().toString();

After executing this getting this result

Hello+how+r+u%0A+Http%3A%2F%2Fwww.google.com%0A%0ATesting+url

And actual result want like this

Hello how r u?
http://www.google.com

Testing url

Thanks in advance

Upvotes: 0

Views: 4946

Answers (3)

Renjith
Renjith

Reputation: 3617

Build the dynamic string separating url and the text. For instance, you could do like

String postStr = Hello how r u? %& http://www.google.com

As you can see, I used a combination of symbols as separator.

Now use split the string,

String[] values = postStr.split("%&");

You could also use StringTokenizer class!

Hope this helps!

Upvotes: 0

Bhavesh Patadiya
Bhavesh Patadiya

Reputation: 25830

Try using Beloq Way

you should not encode whole String containing URL.just encode the Part you want to encode and decode.i think below is the Way to go. try it out. though i am not Sure this is the thing you are looking for.

String name=URLEncoder.encode("Hello hw are you?")+"http://www.google.com"+URLEncoder.encode("Testing url");

Hope it will Help somehow.

Upvotes: 1

PaNaVTEC
PaNaVTEC

Reputation: 2503

Try this:

import android.net.Uri;
import android.net.Uri.Builder;

String reqUrl = "http://google.com"
Builder builder = Uri.parse(reqUrl).buildUpon();
builder.appendQueryParameter("mesg", "Value for mesg");
String finalUri = builder.build().toString();

Upvotes: 1

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