CODEWITHSUNDEEP
javaweb-servicesurlwsdl
Sriks
Sriks

Reputation: 678

How to validate WSDL URL is up and running or not from Java?

I wanted to check WSDL url is valid or not from Java code. So that I can use another url based on that.

So I am checking the code like this.

private boolean isValidWsdlURL(String wsdlUrl) 
{
    UrlValidator urlValidator = new UrlValidator();
    if(urlValidator.isValid(wsdlUrl)) 
    {
        return true;
    }
    logger.info("WSDL URL is not valid...");
    return false;
}

But its alwys returning false though I have valid URL. WSDL URL Ex: http://www.sample.com/MyWsdlService?wsdl

Because URL ends with ?wsdl How to check the code? Looks we need only "http://www.sample.com" for UrlValidator to pass.

Upvotes: 4

Views: 21463

Answers (3)

Issam Ressani
Issam Ressani

Reputation: 213

import org.apache.commons.validator.UrlValidator;

public class ValidateUrlExample{

public static void main(String[] args) {

    UrlValidator urlValidator = new UrlValidator();

    //valid URL
    if (urlValidator.isValid("http://www.mkyong.com")) {
       System.out.println("url is valid");
    } else {
       System.out.println("url is invalid");
    }

    //invalid URL
    if (urlValidator.isValid("http://invalidURL^$&%$&^")) {
        System.out.println("url is valid");
    } else {
        System.out.println("url is invalid");
    }}

}

for more informations: https://www.mkyong.com/java/how-to-validate-url-in-java/

Upvotes: 0

Sriks
Sriks

Reputation: 678

Try this.. Its working for me now. Thanks @zaske

public class TestWSDL {

public static void main(String args[]) {
    String urlStr = "http://www.example.com:8080/helloService?wsdl";
    URL url = null;
    URLConnection urlConnection = null;
    try {
      url = new URL(urlStr);
      urlConnection = url.openConnection();
      if(urlConnection.getContent() != null) {
          System.out.println("GOOD URL");
      } else {
          System.out.println("BAD URL");
      }
    } catch (MalformedURLException ex) {
       System.out.println("bad URL");
    } catch (IOException ex) {
       System.out.println("Failed opening connection. Perhaps WS is not up?");
    } 
}

}

Upvotes: 1

Yair Zaslavsky
Yair Zaslavsky

Reputation: 4137

You're trying to validate a WSDL URL? Why not use the java.net.URL class ?
And do something like:

String urlStr = "http://www.example.com/helloService?wsdl";
URL url = null;
try {
  url = new URL(urlStr);
  URLConnection urlConnection = url.openConnection()
} catch (MalformedURLException ex) {
   System.out.println("bad URL");
} catch (IOException ex) {
   System.out.println("Failed opening connection. Perhaps WS is not up?");
}

When I inserted bad URLs like htt2p instead of http I got - "bad url" print

Upvotes: 3

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