CODEWITHSUNDEEP
javaxmlxslt
user1532390
user1532390

Reputation: 313

javax.xml.transform.Transformer ignoring prefixes?

I am trying to parse a very simple example:

<?xml version="1.0" encoding="UTF-8"?>
<root xmlns:openSearch='http://a9.com/-/spec/opensearch/1.1/'>
    <openSearch:totalResults>100</openSearch:totalResults>
</root>

The stylesheet I am using is the following:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
                version="1.0" 
                xmlns:app='http://www.w3.org/2007/app' >
<xsl:output method="xml" indent="yes"/>
<xsl:preserve-space elements="*"/>
<xsl:template match="/">
    <results>
        <xsl:attribute name="total-results">
                <xsl:value-of 
                 select="atom:root/openSearch:totalResults"/>
        </xsl:attribute>
    </results>
</xsl:template>
</xsl:stylesheet>

This works in libxslt, no problem. I am trying to perform the same task in java now, and I am trying to use the javax.xml.transform package to perform this. Instead of the expected result, it provides an empty value for the total-results attribute. However when I change the value-of to this:

                <xsl:value-of select="root/totalResults"/>

It works. Changing the xml and the xslt is not an option. Is there a parameter I should be setting somewhere? The code is pretty straightforward:

InputSource xmlSource = new InputSource( new StringReader(xml) );

DocumentBuilder builder = factory.newDocumentBuilder();
document = builder.parse(xmlSource);

// Use a Transformer for output
TransformerFactory tFactory = TransformerFactory.newInstance();


StreamSource stylesource = new StreamSource(new StringReader(styleSheet));
Transformer transformer = tFactory.newTransformer(stylesource);

StringWriter writer = new StringWriter();

DOMSource source = new DOMSource(document);
StreamResult result = new StreamResult(writer);
transformer.transform(source, result);

stringResult = writer.toString();

Upvotes: 3

Views: 6819

Answers (1)

Marimuthu Madasamy
Marimuthu Madasamy

Reputation: 13531

In the stylesheet, you are missing the namespace declarations for "atom" and "openSearch". The following works:

  1. Add the "openSearch" namespace (copied from xml) in the stylesheet
  2. Remove the "atom" namespace since there is no information on this namespace
  3. Set the factory as namespace aware: factory.setNamespaceAware(true);

Here is the complete code in Scala (sorry I was too lazy parsing the xml and stylesheet from a file or doing string concatenation in Java):

  def testxsl = {
      val xml = """<?xml version="1.0" encoding="UTF-8"?>
<root xmlns:openSearch='http://a9.com/-/spec/opensearch/1.1/'>
    <openSearch:totalResults>100</openSearch:totalResults>
</root>
      """
      val styleSheet = """<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0" 
        xmlns:app='http://www.w3.org/2007/app' 
        xmlns:openSearch='http://a9.com/-/spec/opensearch/1.1/'>
<xsl:output method="xml" indent="yes"/>
<xsl:preserve-space elements="*"/>
<xsl:template match="/">
    <results>
        <xsl:attribute name="total-results">
                <xsl:value-of select="root/openSearch:totalResults"/>
        </xsl:attribute>
    </results>
</xsl:template>
</xsl:stylesheet>
        """
    val xmlSource = new InputSource( new StringReader(xml) );
    val factory = DocumentBuilderFactory.newInstance();
    factory.setNamespaceAware(true);
    val builder = factory.newDocumentBuilder();
    val document = builder.parse(xmlSource);

    // Use a Transformer for output
    val tFactory = TransformerFactory.newInstance();


    val stylesource = new StreamSource(new StringReader(styleSheet));
    val transformer = tFactory.newTransformer(stylesource);

    val writer = new StringWriter();

    val source = new DOMSource(document);
    val result = new StreamResult(writer);
    transformer.transform(source, result);
    writer.toString(); 
  }

Upvotes: 5

Related Questions