Reputation: 305
I am trying to compile an if statement to check if a reply type is Single
or Multiple
by checking the mysqli variable. If Single
then output options as radio buttons, if Multiple
then output options as checkboxes.
But I am receiving an undefined variable error inside the if statement for $qandaReplyType
. How can this problem be solved?
Code below:
$qandaquery = "SELECT q.QuestionId, r.ReplyType
FROM Question q
LEFT JOIN Reply r ON q.ReplyId = r.ReplyId
WHERE SessionId = ?
GROUP BY q.QuestionId
ORDER BY RAND()";
$qandaqrystmt=$mysqli->prepare($qandaquery);
// get result and assign variables (prefix with db)
$qandaqrystmt->execute();
$qandaqrystmt->bind_result($qandaQuestionId,$qandaReplyType);
$arrReplyType = array();
while ($qandaqrystmt->fetch()) {
$arrReplyType[ $qandaQuestionId ] = $qandaReplyType;
}
$qandaqrystmt->close();
function ExpandOptionType($option) {
$options = explode('-', $option);
if(count($options) > 1) {
$start = array_shift($options);
$end = array_shift($options);
do {
$options[] = $start;
}while(++$start <= $end);
}
else{
$options = explode(' or ', $option);
}
if($qandaReplyType == 'Single'){
foreach($options as $indivOption) {
echo '<div class="ck-button"><label class="fixedLabelCheckbox"><input type="radio" name="options_<?php echo $key; ?>[]" id="option-' . $indivOption . '" value="' . $indivOption . '" /><span>' . $indivOption . '</span></label></div>';
}
}else if($qandaReplyType == 'Multiple'){
foreach($options as $indivOption) {
echo '<div class="ck-button"><label class="fixedLabelCheckbox"><input type="checkbox" name="options_<?php echo $key; ?>[]" id="option-' . $indivOption . '" value="' . $indivOption . '" /><span>' . $indivOption . '</span></label></div>';
}
}
}
foreach ($arrQuestionId as $key=>$question) {
echo ExpandOptionType(htmlspecialchars($arrOptionType[$key]));
}
?>
Upvotes: 1
Views: 1862
Reputation: 12305
Mmmmmmm.....your function....try this:
function ExpandOptionType($option) {
$qandaReplyType = "Single";
$options = explode('-', $option);
if(count($options) > 1) {
$start = array_shift($options);
$end = array_shift($options);
do {
$options[] = $start;
}while(++$start <= $end);
}
else{
$options = explode(' or ', $option);
}
if($qandaReplyType == 'Single'){
foreach($options as $indivOption) {
echo '<div class="ck-button"><label class="fixedLabelCheckbox"><input type="radio"
name="options_<?php echo $key; ?>[]" id="option-' . $indivOption . '" value="' .
$indivOption . '" /><span>' . $indivOption . '</span></label></div>';
}
}else if($qandaReplyType == 'Multiple'){
foreach($options as $indivOption) {
echo '<div class="ck-button"><label class="fixedLabelCheckbox"><input type="checkbox" name="options_<?php echo $key; ?>[]" id="option-' . $indivOption . '" value="' . $indivOption . '" /><span>' . $indivOption . '</span></label></div>';
}
}
}
If this works, then $qandaReplyType is not defined "inside" the function....you should find a way to recover that value o maybe add another parameter to the function and pass the $qandaReplyType value, like:
function ExpandOptionType($option,$qandaReplyType)
Saludos ;)
Upvotes: 0
Reputation: 20889
$qandaReplyType
doesn't exist inside the function.
You'll need to include global $qandaReplyType
inside the function before you can use the global version of the variable.
Couldn't hurt to brush up on variable scope in PHP.
Edit: By the looks of it, $arrQuestionId
and $arrOptionType
aren't in the function scope either.
global $qandaReplyType, $arrQuestionId, $arrOptionType;
Upvotes: 3