CODEWITHSUNDEEP
c++arraysvector
user1764386
user1764386

Reputation: 5611

C++ print contents of array of string vectors?

I don't know C++, but need to make some adjustments to some code I have inherited. One part of the code has:

  array<vector<string>, 2> names;

I am now trying to print the contents of each vector in this array. How do I go about doing that?

I know I can iterate over one vector like this:

  for (unsigned int p=0; p<vector.size(); p++)
      cout << vector.at(p) << endl;

I can not figure out how to adjust this to print the contents of each vector in the array though.

Thank you for any help you can provide. I'm out of my element here.

Upvotes: 0

Views: 1046

Answers (4)

us2012
us2012

Reputation: 16253

One-line solution (not necessarily preferable in this case because manually iterating with for as in Rapptz' answer is easier to read, but still nice to know):

std::for_each(names.begin(), names.end(), [](vector<string>& v){
              std::copy(v.begin(),v.end(),
                        std::ostream_iterator<string>(std::cout,"\n")});

Upvotes: 0

Rapptz
Rapptz

Reputation: 21317

In C++11 you can iterate through this pretty easily.

for(auto& i : names) {
    for(auto& k : i) {
        std::cout << k << std::endl;
    }
}

Upvotes: 2

billz
billz

Reputation: 45410

Just like iterate through vector, you need to iterate through array:

for (int i=0; i<2; i++)
 {
   for (unsigned int p=0; p<names[i].size(); p++)
   {
        cout << names[i].at(p) << endl;
   }
 }

Or

for (auto it = std::begin(names); it != std::end(names); ++it)
 {
   for (unsigned int p=0; p<(*it).size(); p++)
   {
        cout << (*it).at(p) << endl;
   }
 }

Upvotes: 0

teambob
teambob

Reputation: 2084

Using iterators:

array<vector<string>,2> names;

for (array<vector<string>,2>::iterator i=names.begin();i!=names.end();i++)
{
  for (vector<string>::iterator j=i->begin();j!=i->end();j++)
  {
    cout << *j << endl;
  }
}

Upvotes: 0

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