CODEWITHSUNDEEP
pythonregex
scc
scc

Reputation: 10696

Regex to catch at least 1 punctuation character in word

I am trying to get all words that have inside them at least 1 punctuation mark (or any non space, non alphanumeric character) in the beginning, middle and/or end. So for example, in this sentence

this is a wo!rd right !and| other| hello |other

the regex would return 

wo!rd !and| other| |other

Upvotes: 0

Views: 2454

Answers (1)

Rohit Jain
Rohit Jain

Reputation: 213223

You can use this:

>>> sentence = "this is a wo!rd right !and| other| hello |other"

>>> import re

>>> re.findall("\S*[^\w\s]\S*", sentence)
['wo!rd', '!and|', 'other|', '|other']

This will find all those words, containing at least 1 non-word, non-space character. \S is same as [^\s].

Regex Explanation: 

\S*      # Match 0 or more non-space character
[^\w\s]  # Match 1 non-space non-word character
\S*      # Match 0 or more non-space character

Upvotes: 8

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