CODEWITHSUNDEEP
xmlxsltxpath
user994612
user994612

Reputation: 33

Iterate and compare one value with other

I have a following XML data:

<Product>
  <item>
   <ProductVariant>
     <item>
        <VariantType>1</VariantType>
     </item>
     <item>
        <VariantType>2</VariantType>
     </item>
     <item>
        <VariantType>3</VariantType>
     </item>
   </ProductVariant>
   <ChosenVariantType>2</ChosenVariantType>
  </item>
</Product>

and than I have an xsl transformation:

<xsl:for-each select="Product/item/ProductVariant">
    <xsl:if test="(item/VariantType = ../ChosenVariantType)">
        <xsl:value-of name="test" select="item/VariantType"/>
        <xsl:text>-</xsl:text>
        <xsl:value-of name="testChosen" select="../ChosenVariantType"/>
    </xsl:if>   
</xsl:for-each>

which prints out: 1-2

so the question is why 'if' evaluates as true if VariantType is 1 and ChosenVariantType is 2 ?

Upvotes: 1

Views: 48

Answers (1)

Tim C
Tim C

Reputation: 70618

You are iterating over ProductVariant of which there is only one in your XML. When you do your xsl:if condition, all you are testing is whether there is any item under the current ProductVariant with a matching VariantType. In your case, there is. But when you do the xsl:value-of, it will ouptut the value of the first item, whether it matches the variant type or not.

You could either change you xsl:value-of to this:

<xsl:value-of name="test" select="item[VariantType = ../ChosenVariantType]/VariantType"/>

(Although this is rather pointless because you know the VariantType matches ChosenVariantType).

Or maybe you need to iterate over item elements here?

<xsl:for-each select="Product/item/ProductVariant/item">
    <xsl:if test="(VariantType = ../../ChosenVariantType)">
        <xsl:value-of name="test" select="VariantType"/>
        <xsl:text>-</xsl:text>
        <xsl:value-of name="testChosen" select="../../ChosenVariantType"/>
    </xsl:if>   
</xsl:for-each>

Upvotes: 2

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