CODEWITHSUNDEEP
phpjavascriptajax
rpsep2
rpsep2

Reputation: 3111

keep getting undefined request with ajax

using ajax code:

$.ajaxSetup({
    url: "last-id-test.php",
    type: "POST",
});

$.ajax({
    data: {theinfo: 'forminfo'},      
    success: function(data) {alert(data)},
    error: function (XMLHttpRequest, textStatus, errorThrown){alert('Error submitting request.')}   
});

and then simple php of last-id-test.php:

$showme = $_GET['theinfo'];

I always get the error 'undefined index - theinfo'...

I cant see my mistake?

Upvotes: 0

Views: 75

Answers (2)

Ali W
Ali W

Reputation: 376

As mentioned in the comments GET and POST methods result in data being passed in to different global variables in PHP -- GET == $_GET POST == $_POST

So in this case try in your php:

$showme = $_POST['theinfo'];

Useful for debugging is

print_r($_GET); // or $_POST or $_COOKIE

More info on these global variables: http://www.php.net/manual/en/reserved.variables.php

Upvotes: 1

Ghazanfar Mir
Ghazanfar Mir

Reputation: 3543

Try following:

$.ajaxSetup({
    url: "last-id-test.php",
    type: "POST",
});

$.ajax({
    data: {'theinfo': 'forminfo'},      
    success: function(data) {alert(data)},
    error: function (XMLHttpRequest, textStatus, errorThrown){alert('Error submitting request.')}   
});

Note that the single quotes are used around the variable name.

Now you need to access the passing variable using POST array since your type is set as POST

$showme = $_POST['theinfo'];

Upvotes: 1

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