CODEWITHSUNDEEP
javascriptregex
CodyBugstein
CodyBugstein

Reputation: 23322

Regex: Capturing all digits in a string, and returning as a new string of digits

I am trying to capture all the digits of an input string. The string can also contain other characters like letters so I can't simply do [0-9]+.

I've tried /[0-9]/g but this returns all digits as an array.

How do you capture, or match, every instance of a digit and return as a string?

Upvotes: 3

Views: 4508

Answers (3)

Rohit Jain
Rohit Jain

Reputation: 213223

You can replace all the non-digits character rather than extracting the digits:

var str = "some string 22 with digits 2131";
str = str.replace(new RegExp("\D","g"),"");

\D is same as [^\d].

Upvotes: 1

Andrew Clark
Andrew Clark

Reputation: 208435

Just replace all the non-digits from the original string:

var s = "foo 123 bar 456";
var digits = s.replace(/\D+/g, "");

Upvotes: 3

Evan Davis
Evan Davis

Reputation: 36592

The other solutions are better, but to do it just as you asked, you simply need to join the array.

var str = "this 1 string has 2 digits";
var result = str.match(/[0-9]+/g).join(''); // 12

Upvotes: 1

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