CODEWITHSUNDEEP
php
ONYX
ONYX

Reputation: 5859

array and if statment of $_POST array is wrong

How do i iterate over the $departments array and test to see if it equals the $name variable value and return "checked" if its in the list. departments is an array of checkboxes

function isChecked($name) {
$departments = (isset($_POST["interests"])) ? $_POST["interests"] : array();
foreach ($departments as $key => $value) {
    // this next line here is wrong 
    if($departments[$key][$value] == $name) { 
        return "checked";   
    };      
}
return "";

}

Upvotes: 0

Views: 48

Answers (4)

Keith A
Keith A

Reputation: 801

instead of if($departments[$key][$value] == $name)

use 

if($value == $name)

Upvotes: 1

Austin Brunkhorst
Austin Brunkhorst

Reputation: 21130

Try this.

function isChecked($name) {
    return isset($_POST['interests'][$name]);
}

If you need the function to return the string value checked if true, you can do this.

return isset($_POST['interests'][$name]) ? 'checked' : '';

Upvotes: 0

Dane Hillard
Dane Hillard

Reputation: 900

You want to use either

if ($departments[$key] == $name) { ... }

or

if ($value == $name) { ... }

$department[$key] gives you the value at $key in the $department array, but that value is also helpfully stored in $value since you set it up in the loop definition.

Upvotes: 0

Chris Bornhoft
Chris Bornhoft

Reputation: 4301

You're referring to the $value wrong inside the foreach loop. $value contains just what it says, the value of what is inside the $departments array.

function isChecked($name) {
$departments = (isset($_POST["interests"])) ? $_POST["interests"] : array();
foreach ($departments as $key => $value) {
    if($value == $name) { 
        return "checked";   
    };  
}
return "";
}

Upvotes: 1

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