CODEWITHSUNDEEP
java
Taobitz
Taobitz

Reputation: 556

Java modulus operator and PreIncrement - SCJA

Im revising for my SCJA exam at the minute and im confused by this question and answer. The question is what is the result of running and compiling the code. 

    public class Test{ 
       public static void main(String args[]){
         int counter = 0;
         for(int i=0; i< 4; ++i){
            for(int k=0; k< 4; ++k){
               system.out.println("Hello - "+ ++counter);
               if((k % 4) == 0)
               break;
            }
         }
       }
    }

So the answer they give is "Hello-1" because 0 % 4 = 0 But my question is should k not be 1 because its been pre-incremented?

Thanks in advance!

Upvotes: 0

Views: 65

Answers (3)

Jasjeev
Jasjeev

Reputation: 425

k cannot be 1. This is because when a for loop runs, it only updates after it has executed all the code within the loop. Since the loop breaks even before the first iteration is completed, k remains 0.

Upvotes: 0

jlordo
jlordo

Reputation: 37813

A for loop has the following structure:

for (initialization; condition; update)

The update is executed after every execution of the loop.

Therefore the following two loops are identical:

for (int i = 0; i < 10; i++) {

and

for (int i = 0; i < 10; ++i) {

Upvotes: 2

NPE
NPE

Reputation: 500157

my question is should k not be 1 because its been pre-incremented?

The ++k happens at the end of the loop iteration, i.e. after the if statement.

It makes no difference whether it's ++k or k++; in either case the first value of k is zero.

So the answer they give is "Hello-1"

This is clearly incorrect, since counter is never incremented and stays at zero throughout the program.

Upvotes: 1

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