Reputation: 26409
I need a function that concatenates multiple values into (simple) vector, similar to (concatenate )
. However, unlike concatenate, it should be able to handle arguments that are not vectors or sequences.
I.e. it should work like this:
(concat #(1 2) 3) => #(1 2 3)
(concat 1 2 3) => #(1 2 3)
(concat 1 #(2 3 4)) => #(1 2 3 4)
(concat #(1 2) 2 #(3 4 5)) => #(1 2 3 4 5)
How can I do this? I think I've forgotten some trivial lisp construct that makes it possible.
As far as I can tell, concatenate can't do it. and I'm not quite sure how to use make it with macro (there's ,@
consturct that inserts list into resulting lisp form, but but I'm not quite sure how to distinguish between non-sequences and sequences in this case).
Upvotes: 4
Views: 1276
Reputation: 139261
Since we can compute the length of the sequence, we can allocate the result sequence and then copy the elements into it.
(defun concat (type &rest items)
(let* ((len (loop for e in items
if (typep e 'sequence)
sum (length e)
else sum 1))
(seq (make-sequence type len)))
(loop with pos = 0
for e in items
if (typep e 'sequence)
do (progn
(setf (subseq seq pos) e)
(incf pos (length e)))
else
do (progn
(setf (elt seq pos) e)
(incf pos)))
seq))
CL-USER 17 > (concat 'string "abc" #\1 "def" #\2)
"abc1def2"
Above works well for vectors. A version for lists is left as an exercise.
Upvotes: 3
Reputation: 3180
defun my-concatenate (type &rest vectors)
(reduce (lambda (a b)
(concatenate
type
(if (typep a 'sequence) a (list a))
(if (typep b 'sequence) b (list b))))
vectors))
You can use reduce
with a little modification of #'concatenate
on your arguments. If one of the arguments is not a sequence, just transform it into a list (concatenate works even with mixed arguments of simple-vectors and lists).
CL-USER> (my-concatenate 'list #(1 2 3) 3 #(3 5))
(1 2 3 3 3 5)
CL-USER> (my-concatenate 'simple-vector #(1 2 3) 3 #(3 5))
#(1 2 3 3 3 5)
CL-USER> (my-concatenate 'simple-vector 1 #(2 3) (list 4 5))
#(1 2 3 4 5)
EDIT: well, you should probably accept the other answer.
Upvotes: 1
Reputation: 60014
The reduce
approach in the other reply is quadratic in time.
Here is a linear solution:
(defun my-concatenate (type &rest args)
(apply #'concatenate type
(mapcar (lambda (a) (if (typep a 'sequence) a (list a)))
args)))
Upvotes: 5