CODEWITHSUNDEEP
php
saplingPro
saplingPro

Reputation: 21329

passing the reference of the function as an argument

How can I pass the reference of a function to another function as an argument ? I was trying to implement a callback and I need to pass the reference of the function returnProduct before.How do I do that ?

<?php
class Tester {
    public function calculate($var_1,$var_2,$var_3) {
        $product = var_3($var_1,$var_2);
        echo $product;
    }

    public function returnProduct($var_1,$var_2) {
        return $var_1*$var_2;   
    }
}

$obj = new Tester();
$obj->calculate(100,2,$obj->returnProduct);

Upvotes: 3

Views: 63

Answers (2)

Phil
Phil

Reputation: 164742

If you only wanted to use a method of Tester, you can pass the method name as a string, eg

public function calculate($var_1, $var_2, $var_3) {
    $product = $this->$var_3($var_1, $var_2);
    echo $product;
}

Then call it with

$obj->calculate(100, 2, 'returnProduct');

To err on the side of caution, you can check if the method exists using the aptly named method_exists()

Upvotes: 1

Niet the Dark Absol
Niet the Dark Absol

Reputation: 324620

Change your $product = line to:

$product = call_user_func($var_3,$var_1,$var_2);

And change your calling line to:

$obj->calculate(100,2,array($obj,'returnProduct'));

Upvotes: 3

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