CODEWITHSUNDEEP
regexregex-lookarounds
inmank kar
inmank kar

Reputation: 55

Regex pattern construction to avoid selective character based on condition

I have tried the following and the o/p is expected.

String valueIn = test-3-4-HH{3-4}-FF{38-99}
String[] valueInSplit = valueIn.split("-");

o/p array = [test, 3, 4, HH{3, 4}, FF{38, 99}]

Is it possible in regex to to create a patter which avoids the "-" between "{" and "}" so the expected o/p should be

o/p array = [test, 3, 4, HH{3-4}, FF{38-99}]

Is there any other way to do it. Kindly help.

Upvotes: 1

Views: 71

Answers (2)

nhahtdh
nhahtdh

Reputation: 56809

It is possible, with the assumption that there is only 1 level of bracket {}, and the brackets are open and closed properly. Use this regex with split function:

-(?![^{}]*})

As String literal:

"-(?![^{}]*})"

The regex checks that the - is currently not inside bracket, by checking whether we can find a closing bracket } from the current position of the string, given that the character in between does not have an opening bracket { or closing bracket }.

Upvotes: 1

ohaal
ohaal

Reputation: 5268

You can achieve this using a negative lookahead in your split. Basically you check if there is a number and a closing bracket after the seperator -.

Here is what I ended up with:

-(?!\d+\})

Upvotes: 1

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