CODEWITHSUNDEEP
inheritancesuperclass
Hoser
Hoser

Reputation: 5044

Understanding method calls in a super() call

If I have a class 

class Foo{
    String name;
    public Foo(String s){
        name=s;
    }

    public void setName(String s){
        name=s;
    }

    public String getName(){
        return name;
    }
}

and then

class FooBar extends Foo {
    public FooBar(String S){
        super(s);
    }
}

and my main method is

public static void main(String[] args){
    FooBar item1 = new FooBar("Jim");
}

Will the super() call in class FooBar then call the constructor for Foo() and properly set the name to s? Is this what a plain super() call does? Call the constructor of the class being extended?

Upvotes: 0

Views: 54

Answers (2)

Thomas
Thomas

Reputation: 5148

Yes, that is exactly what it does. It calls the constructor for the super / base class.

Upvotes: 2

iTech
iTech

Reputation: 18460

super always refers to your parent class. The sequence of code execution will be as follows:

new FooBar("Jim"); -> super(s); -> Foo(String s) which will set name=s

You do not have a default constructor so there is no super() (i.e. without arguments) since you cannot create an instance of FooBar without a String argument

Upvotes: 1

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