CODEWITHSUNDEEP
phpclassreflection
h2ooooooo
h2ooooooo

Reputation: 39532

Getting class of variable

How can I figure out in what class a reference to a variable was initiated (and currently exists)?

Example:

<?php
    class MyClass {
        public $array = array(
            "this",
            "is",
            "an",
            "array"
        );
    }
    
    $class = new MyClass();
    $arrayReference = &$class->array;
    GetClassForVariable($arrayReference); //Should return "MyClass"
?>

My best bet is some kind of Reflection, but I haven't found any functions that seem suitable for this.

Edit:

A better suited example for what I want is the following:

<?php
    class API_Module {
        public $module;
        public $name;
        private $methods = array();
        public function __construct($module, $name) {   
            $this->module = $module;
            $this->name = $name;
            $this->methods["login"] = new API_Method($this, "login", "Login");
        }
        public function GetMethod($method) {
            return $this->methods[$method];
        }
        public function GetURL() {
            return $this->module; //Should return "session"
        }
    }
    class API_Method {
        public $method;
        public $name;
        private $parentReference;
        private $variables = array();
        public function __construct(&$parentReference, $method, $name) {
            $this->parentReference = $parentReference;
            $this->method = $method;
            $this->name = $name;
            $this->variables["myvar"] = new API_Variable($this, "myvar");
        }
        public function GetURL() {
            return $this->GetParentURL() . "/" . $this->method; //Should return "session/login"
        }
        public function GetVariable($variableName) {
            return $this->variables[$variableName];
        }
        private function GetParentURL() {
            // Need to reference the class parent here
            return $this->parentReference->GetURL();
        }
    }
    class API_Variable {
        public $name;
        private $parentReference;
        public function __construct(&$parentReference, $name) {
            $this->parentReference = $parentReference;
            $this->name = $name;
        }
        public function GetURL() {
            return $this->GetParentURL() . "/" . $this->name; //Should return "session/login/myvar"
        }
        private function GetParentURL() {
            // Need to reference the class parent here
            return $this->parentReference->GetURL();
        }
    }
    
    $sessionModule = new API_Module("session", "Session");
    var_dump($sessionModule->GetMethod("login")->GetVariable("myvar")->GetURL()); //Should return "session/login/myvar"
?>

Now, this works fine, but I'd love to be able to do this without using $parentReference in every single subvariable. It might not be possible, but I'd love to know whether it is or not.

Upvotes: 0

Views: 170

Answers (2)

hakre
hakre

Reputation: 197659

For your example:

$class = new MyClass();
$arrayReference = &$class->array;
GetClassForVariable($arrayReference); //Should return "MyClass"

to find out to which variable originally the alias $arrayReference refers to is not possible in PHP. There is no function available resolving the aliases.

Additionally $class->array is just a variable on it's own. So you would also need to find out based on a value in which class it was defined. That is not possible as well, similar to that PHP does not offer anything to resolve a variable alias, it also does not offer anything to learn about the definition of a variable.

So in short PHP does not have a ReflectionVariable class available ;) I wonder if it is even possible.

Upvotes: 1

Hendeca
Hendeca

Reputation: 943

The get_class() function should work:

http://php.net/manual/en/function.get-class.php

I agree with GRoNGoR that you shouldn't need to get the parent class of a property of an instantiated object. You could instead just get the name of the class before accessing the property. For example:

$class = new MyClass();
$parent_class = get_class($class); // returns "MyClass"
$arrayReference = &$class->array;

Not sure why you'd need the parent class of the property when you have the object instance and can easily get the parent class from there.

Upvotes: 0

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