Reputation: 6323
I wrote functions to convert 100,000 hex strings to values, but it takes 10 seconds to perform on the whole array. Does Matlab have a function to do this, so that it is faster, ... ie: less than 1 second for the array?
function x = hexstring2dec(s)
[m n] = size(s);
x = zeros(1, m);
for i = 1 : m
for j = n : -1 : 1
x(i) = x(i) + hexchar2dec(s(i, j)) * 16 ^ (n - j);
end
end
function x = hexchar2dec(c)
if c >= 48 && c <= 57
x = c - 48;
elseif c >= 65 && c <= 70
x = c - 55;
elseif c >= 97 && c <= 102
x = c - 87;
end
Upvotes: 1
Views: 3384
Reputation: 114796
shoelzer's answer is obviously the best.
However, if you want to do the conversion by yourself, then you might find this useful:
Assuming s
is a char matrix: all hex numbers are of the same length (zero padded if necessary) and each row has a single number. Then
ds = double( upper(s) ); % convert to double
sel = ds >= double('A'); % select A-F
ds( sel ) = ds( sel ) - double('A') + 10; % convert to 10 - 15
ds(~sel) = ds(~sel) - double('0'); % convert 0-9
% do the sum through vector product
v = 16.^( (size(s,2)-1):-1:0 );
x = s * v(:);
Upvotes: 2