davy
davy

Reputation: 33

!is.na creates NAs in other columns

In the midst of merging several data sets, I'm trying to remove all rows of a data frame that have a missing value for one particular variable (I want to keep the NAs in some of the other columns for the time being). I used the following line:

data.frame <- data.frame[!is.na(data.frame$year),]

This successfully removes all rows with NAs for year, (and no others), but the other columns, which previously had data, are now entirely NAs. In other words, non-missing values are being converted to NA. Any ideas as to what's going on here? I've tried these alternatives and got the same outcome:

data.frame <- subset(data.frame, !is.na(year))

data.frame$x <- ifelse(is.na(data.frame$year) == T, 1, 0);
data.frame <- subset(data.frame, x == 0)

Am I using is.na incorrectly? Are there any alternatives to is.na in this scenario? Any help would be greatly appreciated!

Edit Here is code that should reproduce the issue:

#data
tc <- read.csv("http://dl.dropbox.com/u/4115584/tc2008.csv")
frame <- read.csv("http://dl.dropbox.com/u/4115584/frame.csv")

#standardize NA codes
tc[tc == "."] <- NA
tc[tc == -9] <- NA

#standardize spatial units
colnames(frame)[1] <- "loser"
colnames(frame)[2] <- "gainer"
frame$dyad <- paste(frame$loser,frame$gainer,sep="")
tc$dyad <- paste(tc$loser,tc$gainer,sep="")
drops <- c("loser","gainer")
tc <- tc[,!names(tc) %in% drops]
frame <- frame[,!names(frame) %in% drops]
rm(drops)

#merge tc into frame
data <- merge(tc, frame, by.x = "year", by.y = "dyad", all.x=T, all.y=T) #year column is duplicated in       this process. I haven't had this problem with nearly identical code using other data.

rm(tc,frame)

#the first column in the new data frame is the duplicate year, which does not actually contain years.   I'll rename it.
colnames(data)[1] <- "double"

summary(data$year) #shows 833 NA's

summary(data$procedur) #note that at this point there are non-NA values

#later, I want to create 20 year windows following the events in the tc data. For simplicity, I want to remove cases with NA in the year column.

new.data <- data[!is.na(data$year),]

#now let's see what the above operation did
summary(new.data$year) #missing years were successfully removed
summary(new.data$procedur) #this variable is now entirely NA's

Upvotes: 1

Views: 10567

Answers (2)

Arun
Arun

Reputation: 118799

I think the actual problem is with your merge.

After you merge and have the data in data, if you do:

# > table(data$procedur, useNA="always")

#   1      2      3      4      5      6   <NA> 
# 122    112    356     59     39     19 192258 

You see there are these many (122+112...+19) values for data$procedur. But, all these values are corresponding to data$year = NA.

> all(is.na(data$year[!is.na(data$procedur)]))
# [1] TRUE # every value of procedur occurs where year = NA

So, basically, all values of procedur are also removed because you removed those rows checking for NA in year.

To solve this problem, I think you should use merge as:

merge(tc, frame, all=T) # it'll automatically calculate common columns
# also this will not result in duplicated year column.

Check if this merge gives you the desired result.

Upvotes: 2

Matt LaFave
Matt LaFave

Reputation: 569

Try complete.cases:

data.frame.clean <- data.frame[complete.cases(data.frame$year),]

...though, as noted above, you may want to pick a more descriptive name.

Upvotes: 0

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