Reputation: 6587
I am trying to create switch buttons with on/off states(Using twitter bootstrap).
In this demo you can see that i have outer border to button. Button draggable is true to x-Offset.
I want button not to go out of my boundary. So i put it in a div
element and set it to some width.
I don't think it is going good.
Please suggest me what can i do to bound this button in border area.
Fiddle link- http://jsfiddle.net/stackmanoz/w6AsC/3/
Some code shelf-
<div style="width:200px;border:1px dashed #ddd">
<p id="button" class="btn-inverse btn">Regular link</p>
</div>
And script-
$(document).ready(function () {
$('#button').draggable({ axis: 'x' });
});
Upvotes: 0
Views: 103
Reputation: 51201
Add an extra parameter as explained in the Docs, your friend and helper.
$('#button').draggable({ axis: 'x',containment: "parent" });
This way you theoretically don't even need the axis parameter.
Upvotes: 2