CODEWITHSUNDEEP
php
Paul Dessert
Paul Dessert

Reputation: 6389

how to access an array in a config file from a class

require_once($_SERVER["DOCUMENT_ROOT"] . 'config.php');

class stuff{

    public $dhb;

    public function __construct(){
        $dbh = new PDO('mysql:host=' . $database['host'] . ';dbname=' . $database['dbname'] . '', $database['user'], $database['password']);
    }
}

In the example above I get this error:

Notice: Undefined variable: database in C:\wamp\www\career\inc\controller.php on line 11

How can I get access to the array I have in config.php? It contains the $database array.

Upvotes: 0

Views: 75

Answers (2)

user1703809
user1703809

Reputation:

What PeeHaa said stands. Another way to do it would be using a singleton class for your config options.

If you still want to do it your way, I assume $database is global, so your constructor should be:

public function __construct(){
        global $database;
        $dbh = new PDO('mysql:host=' . $database['host'] . ';dbname=' . $database['dbname'] . '', $database['user'], $database['password']);
    }

Upvotes: 1

PeeHaa
PeeHaa

Reputation: 72672

Better is to inject the information:

class stuff{

    public $dhb;

    public function __construct($database){
        $dbh = new PDO('mysql:host=' . $database['host'] . ';dbname=' . $database['dbname'] . '', $database['user'], $database['password']);
    }
}

require_once($_SERVER["DOCUMENT_ROOT"] . 'config.php');
$stuff = new stuff($database); // really hope this is a fake name

Or perhaps even better just pass the database instance directly:

class stuff{

    public $dhb;

    public function __construct($dbh){
        $this->dbh = $dbh;
    }
}

require_once($_SERVER["DOCUMENT_ROOT"] . 'config.php');
$dbh = new PDO('mysql:host=' . $database['host'] . ';dbname=' . $database['dbname'] . '', $database['user'], $database['password']);
$stuff = new stuff($dbh); // really hope this is a fake name

Upvotes: 3

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