CODEWITHSUNDEEP
python
user2052251
user2052251

Reputation: 161

Trying to convert string to json in python

I am new to python and I am pretty sure that I am doing something very stupid..

I have a string:

s = '{"l":1,"oE":{"n":"name","rN":["1","2","3","3","5","6","7","8","9","10"],"dir":"out","ed":["1","1","1","1","1","1","1","1","1","1"]}'

I did json.loads(s)

But I am getting an error?

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib/python2.7/json/__init__.py", line 328, in loads
    return _default_decoder.decode(s)
  File "/usr/lib/python2.7/json/decoder.py", line 365, in decode
    obj, end = self.raw_decode(s, idx=_w(s, 0).end())
  File "/usr/lib/python2.7/json/decoder.py", line 381, in raw_decode
    obj, end = self.scan_once(s, idx)
ValueError: Expecting , delimiter: line 1 column 72 (char 72)

Upvotes: 0

Views: 1422

Answers (2)

Wilduck
Wilduck

Reputation: 14136

You're missing a quotation mark in your code. Also a closing brace. Instead of:

s = '{"l":1,"oE":{"n":"name","rN":["1","2","3","3","5","6","7","8","9","10],"dir":"out","ed":["1","1","1","1","1","1","1","1","1","1"]}'

use

s = '{"l":1,"oE":{"n":"name","rN":["1","2","3","3","5","6","7","8","9","10"],"dir":"out","ed":["1","1","1","1","1","1","1","1","1","1"]}}'

You can figure this out from your stack trace:

ValueError: Expecting , delimiter: line 1 column 72 (char 72)

If you look at the 72nd character in that line, you'll see that's where the error occurs.

Upvotes: 2

Robᵩ
Robᵩ

Reputation: 168876

"10] seems to be missing a ". Try "10"] instead.

Upvotes: 0

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