CODEWITHSUNDEEP
javaregexsplitstringtokenizer
javadev
javadev

Reputation: 1669

Splitting a string with delimiters for Strings containing other characters with the same delimiter

I'm trying to split a string like the one : "@WWP2-@POLUXDATAWWP3-TTTTTW@K826" to extract the @WWP2-@POLUXDATAWWP3-TTTTTW and the 826 strings when executing the snippet : 

String expression = "@WWP2-@POLUXDATAWWP3-TTTTTW@K826";
        StringTokenizer tokenizer = new StringTokenizer(expression, "@K");
            if (tokenizer.countTokens() > 0) {
                while (tokenizer.hasMoreTokens()) {
                    System.out.println(tokenizer.nextToken());
                }
            }

while expecting the result to be

WWP2-POLUXDATAWWP3-TTTTTW
826

I'm getting:

WWP2-
POLUXDATAWWP3-TTTTTW
826

Any idea on how to get the exact two strings?

Upvotes: 1

Views: 396

Answers (3)

MikeM
MikeM

Reputation: 13631

String expression = "@WWP2-@POLUXDATAWWP3-TTTTTW@K826";

String [] strArr = expression.split("@K");

for( int i = 0; i < strArr.length; i++ ) {
    System.out.println( strArr[i] );
}

The StringTokenizer splits the string on all the single characters in the delimiter string, i.e. on @ and K.

Also see Why is StringTokenizer deprecated?.

Upvotes: 0

sp00m
sp00m

Reputation: 48807

StringTokenizer will use the given delimiter parameter as a set of chars if it contains more than one char. In your case, it will split your string by @ and by K, while K must not necessarily follow @.

Upvotes: 0

Achintya Jha
Achintya Jha

Reputation: 12843

    String[] str = expression.split("@K");
    System.out.println(Arrays.toString(str));

Try String#split("@K");

Output:

[@WWP2-@POLUXDATAWWP3-TTTTTW, 826]

Upvotes: 4

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