Reputation: 25812
I implemented a non-in-place
version of selection sort in OCaml.
let sort compare_fun l =
let rec find_min l' min_l origin_l =
match l' with
| [] ->
if min_l = [] then (min_l, l')
else
let min = List.hd min_l
in
(min_l, List.filter (fun x -> if x != min then true else false) origin_l)
| x::tl ->
if min_l = [] then
find_min tl [x] origin_l
else
let c = compare_fun (List.hd min_l) x
in
if c = 1 then
find_min tl [x] origin_l
else if c = 0 then
find_min tl (min_l @ [x]) origin_l
else
find_min tl min_l origin_l
in
let rec insert_min l' new_l =
match l' with
| [] -> new_l
| _ ->
let (min_l, rest) = find_min l' [] l'
in
insert_min rest (new_l @ min_l)
in
insert_min l [];;
My idea is that in a list, every time I find the list of minimum items (in case of duplicate values) and add this min list
to the result list, then redo the finding_min in the rest of the list.
I use List.filter
to filter out the min_list
, so the resulting list will be the list for next find_min
.
I find my implementation is quite complicated, and far more complicated than the Java in-place version of selection sort.
Any suggestions to improve it?
Upvotes: 0
Views: 329
Reputation: 9878
Edit: Here's a much better implementation: http://rosettacode.org/wiki/Sorting_algorithms/Selection_sort#OCaml
here's my own crappier implementation
(* partial function - bad habit, don't do this. *)
let smallest (x::xs) = List.fold_right (fun e acc -> min e acc) xs x
let remove l y =
let rec loop acc = function
| [] -> raise Not_found
| x::xs -> if y = x then (List.rev acc) @ xs else loop (x::acc) xs
in loop [] l
let selection_sort =
let rec loop acc = function
| [] -> List.rev acc
| xs ->
let small = smallest xs in
let rest = remove xs small in
loop (small::acc) rest
in loop []
Upvotes: 1