Initializing a c++ string with argv

Question

I have a function that takes a c++ style string. I want to either put argv[1] into a c++ string, or simply pass it directly to my function.

#include <iostream>
#include <string>
using namespace std;

string  rev (string &reverse);

int main(int argc, char argv[])
{
if (argc != 2)
    cout << "Bad Input" << endl;
string reverse = argv[1];
cout << rev(reverse) << endl;   
}

This is what I have so far, but when I do this, I get the following error:

8.4.cpp: In function ‘int main(int, char*)’:
8.4.cpp:11: error: invalid conversion from ‘char’ to ‘const char*’
8.4.cpp:11: error:   initializing argument 1 of ‘std::basic_string<_CharT, _Traits, _Alloc>::basic_string(const _CharT*, const _Alloc&) [with _CharT = char, _Traits = std::char_traits<char>, _Alloc = std::allocator<char>]’

Answer 1

As mentioned argv[] is a pointer, to a block of memory, or a "pointer to a pointer". You simply need to add * to argv[] to make it act such.

A quick Google brought up THIS

Answer 2

Fix main

int main(int argc, char argv[])

// should be

int main(int argc, char  *    argv[]) 
        ///            ^^^^^