Reputation: 1
700 = 17 + 683
702 = 11 + 691
704 = 3 + 701
706 = 5 + 701
As you can see...the 3 and 5 is in the wrong place it should be:
700 = 17 + 683
702 = 11 + 691
704 = 3 + 701
706 = 5 + 701
My code for this:
fprintf(fpout, "%d = %d + %d\n", lower, primeNum1, primeNum2);
I'm assuming I need to use some special technique to resolve this issue. Could someone please help here.
Upvotes: 0
Views: 458
Reputation: 781004
Specify the field widths:
printf(fpout, "%3d = %3d + %3d\n", lower, primeNum1, primeNum2);
Upvotes: 1
Reputation: 385610
You can specify a minimum field width by putting a number between the %
and the d
. When the converted value is shorter than the minimum field width, the field will be padded on the left with spaces.
fprintf(fpout, "%3d = %2d + %3d\n", lower, primeNum1, primeNum2);
Of course, you may need to give some thought to what the appropriate minimum field widths are based on your expected values for lower
, primeNum1
, and primeNum2
.
Upvotes: 1