CODEWITHSUNDEEP
c++qtqwidget
Chris O'Brien
Chris O'Brien

Reputation: 372

QWidget - Not sure where to start

I'm doing a college project in QT with C++. I basically have it all done, but I kind of want to end of a flourish! At the endgame, you get to the last room and press the control panel and a keypad appears (which is a .ui layout created as a QWidget) - the access code is a randomly generated 4 digit number in an earlier room.

Anyways, I want to pop up the QWidget with the keypad, get the user to press 4 buttons - each button would return a QString - and then press the confirm button. If it matches, game ends. If not, returned to room.

I just have no idea how to call the widget! The API haven't really help as I don't see anyway to assign a .ui form to the QWidget object.

Upvotes: 0

Views: 160

Answers (2)

Thomas
Thomas

Reputation: 5138

The .ui file is a resource file. If the setup you have does not do this for you automatically, then you must use the uic tool to convert the .ui file to c++ source code. 

 foo.ui -> ui_foo.h

This header contains a class that creates the widgets and has members to acces each of the members once they have been created.

class Ui_Foo {
   setupUi(QWidget *) { ...
   }
}

namespace Ui {
    class Foo: public Ui_Foo {};
} // namespace Ui

An instance of Ui::Foo is placed in your FooWidget

// FooWidget.h
//
class FooWidget 
: public QWidget {
    FooWidget(QWidget *);
    Ui::Foo  mUi;
}

and its setupUi is called in the constructor of your FooWidget

// FooWidget.cpp
// 
FooWidget::FooWidget(QWidget *parent)
: QWidget(parent)
{
    mUi.setupUi(this);
}

Upvotes: 1

Nikos C.
Nikos C.

Reputation: 51832

The .ui form is a widget. Just call show() on it.

Upvotes: 0

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