CODEWITHSUNDEEP
c#
Xaisoft
Xaisoft

Reputation: 46591

Convert and Display IP Address to Binary form?

Is there a method in c# that would talk the ip address 10.13.216.41

and display it as 00001010.00001101.11011000.00101001. If not, how can it be done?

Upvotes: 4

Views: 8035

Answers (6)

ETK
ETK

Reputation: 1

This method can help you:

static string IPDecToBinary(string IPAdresa)
{
    string IPverBinare = null;
    IPAddress IPDec = IPAddress.Parse(IPAdresa);
    byte[] IPByte = IPDec.GetAddressBytes();

    IPverBinare = string.Format("{0}.{1}.{2}.{3}",
                                 Convert.ToString(IPByte[0], 2).PadLeft(8, '0'),
                                 Convert.ToString(IPByte[1], 2).PadLeft(8, '0'),
                                 Convert.ToString(IPByte[2], 2).PadLeft(8, '0'),
                                 Convert.ToString(IPByte[3], 2).PadLeft(8, '0')
                                 );
    return IPverBinare;
}

Upvotes: 0

Reed Copsey
Reed Copsey

Reputation: 564403

You could do:

var parts = (from p in ("10.13.216.41").Split('.')
              select int.Parse(p)).ToArray();
string result = string.Format("{0}.{1}.{2}.{3}",
    Convert.ToString(part[0], 2).PadLeft(8,'0'),
    Convert.ToString(part[1], 2).PadLeft(8,'0'),
    Convert.ToString(part[2], 2).PadLeft(8,'0'),
    Convert.ToString(part[3], 2).PadLeft(8,'0'));

Upvotes: 0

Richard Szalay
Richard Szalay

Reputation: 84734

While I won't rewrite the format-as-binary code (Larsenal's answer was fine), I'll point out that splitting on "." won't work for IPv6 addresses. If you use IPAddress.Parse, though, it will work for any address format. You can then use IPAddress.GetAddressBytes to get each part of the address.

So instead of:

input.Split('.').Select( ... )

do:

IPAddress.Parse(input).GetAddressBytes().Select( ... )

Upvotes: 10

Larsenal
Larsenal

Reputation: 51156

static string IPAddrToBinary( string input) {
   // assumes a valid IP Address format
   return String.Join(".", (input.Split('.').Select(x => Convert.ToString(Int32.Parse(x), 2).PadLeft(8, '0'))).ToArray());
}

Here's a version with comments, which may be a little easier to understand:

static string IPAddrToBinary(string input)
{
    return String.Join(".", ( // join segments
        input.Split('.').Select( // split segments into a string[]

            // take each element of array, name it "x",
            //   and return binary format string
            x => Convert.ToString(Int32.Parse(x), 2).PadLeft(8, '0')

        // convert the IEnumerable<string> to string[],
        // which is 2nd parameter of String.Join
        )).ToArray());
}

Upvotes: 7

Joel Coehoorn
Joel Coehoorn

Reputation: 415705

Funny, I wrote a javascript version of this today for another question.

Here's the c# translation of that code:

int dottedQuadToInt(string ip)
{      
    var parts = ip.Split(new char[] {'.'}, 4);
    if (parts.Length != 4) return -1;

    var result = 0; 
    var bitPos = 1;

    foreach(var part in parts)
    {
       //validation
       if (part.Length == 0 || part.Length > 3) return -1;

       int segment;
       if (!int.TryParse(part, out segment) || segment<0 || segment > 255) return -1;

       //compute next segment
       result += bitPos * segment;
       bitPos  = bitPos  << 8;
    }
    return result;
}

Now, this isn't exactly what you asked for, but it's arguably more useful and it shoudl point you in the right direction.

Upvotes: 0

Matthew Jones
Matthew Jones

Reputation: 26190

First, you would need to get the number you want to convert to binary (using String.Split, for example). Then, you can use an overload of the Convert.ToString method to return a string of the specified number in the specified base. For example:

Convert.ToString (128, 2);

returns 

10000000

Upvotes: 1

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