CODEWITHSUNDEEP
bash
zyxxwyz
zyxxwyz

Reputation: 193

Shell script to print the number of hours and minutes a user has been logged on?

I'm trying to write a shell script using the date and who commands to print how the number of hours and minutes a user has been logged in. I can assume it is less than 24 hours. How would I do this?

I would think I would somehow extract the time from the date command and from the who command and somehow subtract them, but I'm not sure how I would implement that.

Upvotes: 1

Views: 1572

Answers (1)

Gilles Quénot
Gilles Quénot

Reputation: 185284

#!/bin/bash

export LANG=C

date_string=$(
    who |
    sort -k3M -k4n |
    awk '{if ($1 ~ user) {print $3, $4, $5;exit}}' user="$1"
)
diff_seconds_between_date_and_now=$((
    $(date +%s) - $(date -d "$date_string" +%s)
))
printf "%s %s\n" "$((diff_seconds_between_date_and_now/3600)) hours" \
    "$((diff_seconds_between_date_and_now%3600/60)) minutes"

I takes the oldest line whith the specified user :

Usage : 

$ bash script.bash <USERNAME>

Sample output :

$ bash script.bash sputnick
528 hours 6 minutes

Upvotes: 4

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