CODEWITHSUNDEEP
php
Pat
Pat

Reputation: 649

Using usort for object sorting

I am trying to sort an object array by distance using usort. Here is my sort function:

private function sortDistance ($first, $next)
{
    $d1 = $this->searchDistance[$first->zip];
    $d2 = $this->searchDistance[$next->zip];

    if ($d1 == $d2) {
        return 0;
    }
    return ($d1 > $d2) ? +1 : -1;
}

Here is where I am calling usort:

return usort($searchResults->limit('5', $start)->get()->result(), array("Search", "sortDistance"));

For some reason, when I print_r the returned result, its only printing 1. Am I doing something wrong?

Thanks

Upvotes: 1

Views: 141

Answers (2)

christopher
christopher

Reputation: 27356

Returning usort is returning 1 because the usort function has completed documentation. print_r() the array you just sorted, and you will see the sorted values :)

Working example:

$result = $searchResults->limit('5', $start)->get()->result();
usort($result, array("Search", "sortDistance"));
return $result;

Upvotes: 1

Ray
Ray

Reputation: 41448

Make your sort function static:

 private static function sortDistance ($first, $next){ ...

Also, this will only work for sorting inside the Search class where the method is defined since it is private. To use it in the child classes make it protected, for use anywhere make it public.

Alternately, if you want to method it non-static and you're inside an instance of a Search object, you could make the method non static and call it like this:

  return usort($searchResults->limit('5', $start)->get()->result(), 
                array($this,   "sortDistance"));

Upvotes: 0

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