CODEWITHSUNDEEP
pythonwebsocketpyqt
Alexey Egorov
Alexey Egorov

Reputation: 2410

pyqt and websocket client. listen websocket in background

I have a PyQt Gui application. This application have a main window that should be open after the start.

This application should to listen the websocket.

I tried solve it so: 

...

if __name__ == '__main__':
    app = QtGui.QApplication(sys.argv)

    window = Window()
    window.show()

    websocket.enableTrace(True)
    ws = websocket.WebSocketApp("ws://localhost:8080/chatsocket",
                                on_message = on_message,
                                on_error = on_error,
                                on_close = on_close)
#    ws.on_open = on_open

    ws.run_forever()

    sys.exit(app.exec_())

But, after start application the main window was not open.

Without line "ws.run_forever()" the main window was open but application does not listen websocket.

I need listen the websocket in the "background"? Can you help me?

PS: (Sorry for my english)

Upvotes: 1

Views: 6077

Answers (1)

Alexey Egorov
Alexey Egorov

Reputation: 2410

Thanks enginefree.

I make this

class Window(QtGui.QDialog):
    def __init__(self, parent=None):
        super(Window, self).__init__()

        self.thread = ListenWebsocket()
        self.thread.start()

...


class ListenWebsocket(QtCore.QThread):
    def __init__(self, parent=None):
        super(ListenWebsocket, self).__init__(parent)

        websocket.enableTrace(True)

        self.WS = websocket.WebSocketApp("ws://localhost:8080/chatsocket",
                                on_message = self.on_message,
                                on_error = self.on_error,
                                on_close = self.on_close) 

    def run(self):
        #ws.on_open = on_open

        self.WS.run_forever()


    def on_message(self, ws, message):
        print message

    def on_error(self, ws, error):
        print error

    def on_close(self, ws):
        print "### closed ###"

if __name__ == '__main__':
    app = QtGui.QApplication(sys.argv)

    QtGui.QApplication.setQuitOnLastWindowClosed(False)

    window = Window()
    window.show()

    sys.exit(app.exec_())

Upvotes: 3

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