Reputation: 3
I'm new to Java, but I have done some PSP coding in C before. This seems to be quite different.
Below is the stack trace for what I'm seeing:
java.lang.RuntimeException: An error occured while executing doInBackground()
enter code hereenter code here`at android.os.AsyncTask$3.done(AsyncTask.java:299)
enter code here`at java.util.concurrent.FutureTask$Sync.innerSetException(FutureTask.java:273)
at java.util.concurrent.FutureTask.setException(FutureTask.java:124)
at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:307)
at java.util.concurrent.FutureTask.run(FutureTask.java:137)
at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:230)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1076)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:569)
at java.lang.Thread.run(Thread.java:856)
Caused by: java.lang.ArrayIndexOutOfBoundsException: length=1; index=1
at com.adev.abmp3.ViewSongDialog$FindLyrics.doInBackground(ViewSongDialog.java:173)
at com.adev.abmp3.ViewSongDialog$FindLyrics.doInBackground(ViewSongDialog.java:1)
at android.os.AsyncTask$2.call(AsyncTask.java:287)
at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:305)
And here is the patch of code:
@Override
protected Void doInBackground(Void... arg0) {
String searchQuery = title.replaceAll("[^ \\w]", "");
searchQuery = searchQuery.replace(" ", "+");
String searchResult = httpRun("http://search.azlyrics.com/search.php?q="+searchQuery).toString();
System.out.println("http://search.azlyrics.com/search.php?q="+searchQuery);
if(!searchResult.contains("Sorry, no results") && !searchResult.equals("")) {
String link = searchResult.split("<table width=100%>")[1];
link = link.substring(link.indexOf("<a href=\""), link.indexOf("\" rel"));
link = link.replace("<a href=\"", "");
String lR = httpRun(link).toString();
if(lR != "" && lR.contains("<!-- start of lyrics -->")) {
lR = lR.substring(lR.indexOf("<!-- start of lyrics -->"), lR.indexOf("<!-- end of lyrics -->"));
lR = lR.replace("<!-- start of lyrics -->", "");
lyrics = lR;
} else {
fail = 1;
lyrics = "Couldn't find lyrics";
}
} else {
fail = 1;
lyrics = "Couldn't find lyrics";
}
return null;
}
I've done some research, and have read that you can't print to the screen within doInBackground
- but I'm not sure where to go from here. Any help would be appreciated.
EDIT: java.lang.StringIndexOutOfBoundsException in java.lang.String.startEndAndLength
Heres the new stack:
java.lang.RuntimeException: An error occured while executing doInBackground()
at android.os.AsyncTask$3.done(AsyncTask.java:299)
at java.util.concurrent.FutureTask$Sync.innerSetException(FutureTask.java:273)
at java.util.concurrent.FutureTask.setException(FutureTask.java:124)
at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:307)
at java.util.concurrent.FutureTask.run(FutureTask.java:137)
at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:230)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1076)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:569)
at java.lang.Thread.run(Thread.java:856)
Caused by: java.lang.StringIndexOutOfBoundsException: length=7338; regionStart=537; regionLength=-538
at java.lang.String.startEndAndLength(String.java:593)
at java.lang.String.substring(String.java:1474)
at com.adev.abmp3.ViewSongDialog$FindLyrics.doInBackground(ViewSongDialog.java:174)
at com.adev.abmp3.ViewSongDialog$FindLyrics.doInBackground(ViewSongDialog.java:1)
at android.os.AsyncTask$2.call(AsyncTask.java:287)
at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:305)
Upvotes: 0
Views: 2212
Reputation: 2427
String link = searchResult.split("<table width=100%>")[1];
The error is occuring there. Indices start at 0, and your split is returning an array of size 1, so element 1 is out of bounds, and hence the exception is thrown. If you change it to String link = searchResult.split("<table width=100%>")[0];
the exception will no longer be thrown.
Upvotes: 0
Reputation: 93542
Your split call is returning an array of size 1, but you're trying to get the 2nd item in it (with the [1]). You have to account for the possibility that your split string isn't in the input.
Upvotes: 3