CODEWITHSUNDEEP
c#jsonwindows-8
dubyaa
dubyaa

Reputation: 199

Creating JSON in Windows 8 C# using IJsonValue: Cannot Implicitly convert type 'string' to 'Windows.Data.Json.IJsonValue'

I am creating a Windows 8 App in C# using Visual Studio. I am trying to take a bunch of data input and create a JSON object from that data. Here is my preliminary test method that does not work:

        IJsonValue name = "Alex"; 
        JsonObject Character = new JsonObject();
        Character.Add("Name", name);

The error that I am getting is 

Cannot Implicitly convert type 'string' to 'Windows.Data.Json.IJsonValue'

I looked up the documentation for IJsonValue but couldn't figure out how to create an instance of IJsonValue containing a string. So how do I store data in an IJsonValue to be added to a JsonObject?

Upvotes: 0

Views: 3073

Answers (2)

W.K.S
W.K.S

Reputation: 10095

Here's how you would do it:

JsonObject character = new JsonObject();
character.Add("Name",JsonValue.CreateStringValue("Alex"));

Upvotes: 4

JP Alioto
JP Alioto

Reputation: 45117

The class JsonValue implements the IJsonValue interface. You can create an instance of the class and use it like this for example ...

JsonValue jsonValue = JsonValue.Parse("{\"Width\": 800, \"Height\": 600, \"Title\": \"View from 15th Floor\", \"IDs\": [116, 943, 234, 38793]}");
double width = jsonValue.GetObject().GetNamedNumber("Width");
double height = jsonValue.GetObject().GetNamedNumber("Height");
string title = jsonValue.GetObject().GetNamedString("Title");
JsonArray ids = jsonValue.GetObject().GetNamedArray("IDs");

Check out this for more examples.

Upvotes: 3

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