Reputation: 153
Hello,
I am trying to read a file with a Scanner
so I can use the input of the strings to construct other objects. However my scanner is always throwing a NullPointerException
when trying to create it. I have a pig.txt
text file in the res/raw
folder but my scanner can not seem to access it. I do not know what I am doing wrong. I have comment out other code of the method but still get an exception.
public void loadAchievements() {
try {
Scanner s = new Scanner(getResources().openRawResource(R.raw.pig));
/**
* s = s.useDelimiter("."); Scanner StringScanner; StringScanner =
* new Scanner(s.next()); StringScanner =
* StringScanner.useDelimiter(":"); String keep =
* StringScanner.next(); String StringKeeper = StringScanner.next();
* this.achievementBoard.add(new Achievement_Item(keep,
* StringKeeper)); StringScanner.close(); s.close();
**/
} catch (NullPointerException e) {
e.printStackTrace();
System.out.println("NULLPOINTER");
}
}
Upvotes: 0
Views: 1158
Reputation: 369
I had this problem today, and I resolved somehow.
I know that old question, but I would share it if others have stuck.
public class Question {
private int numberOfQuestion;
private String[] myquestion;
public Question(InputStream file_name) {
Scanner scanner = null;
try {
scanner = new Scanner(file_name);
} catch (Exception e) {
Log.d("Question", "Scanner :" + e);
System.exit(1);
}
this.numberOfQuestion = scanner.nextInt();
scanner.nextLine();
myquestion = new String[numberOfQuestion];
for (int i = 0; i < numberOfQuestion; ++i) {
myquestion[i] = scanner.nextLine();
}
scanner.close();
}
---------------------------------------------------------
call:
try {
MyScanner myScanner = new MyScanner(getResources().openRawResource( R.raw.input_question));
} catch (Exception e) {
Log.d("Error", "input_question.txt");
}
Upvotes: 1
Reputation: 11191
openRawResource() method can only be used to open drawable, sound, and raw resources; it will fail on string and color resources. Since your pig.txt is a text file that contains a String, openRawResource() won't be able to open a new stream therefore your stream is null.
Upvotes: 0