CODEWITHSUNDEEP
mathmatlablinear-algebra
worbel
worbel

Reputation: 6585

Solving a matrix in MATLAB?

How does one solve the (non-trivial) solution Ax = 0 for x in MATLAB?

A = matrix
x = matrix trying to solve for

I've tried solve('A * x = 0', 'x') but I only get 0 for an answer.

Upvotes: 10

Views: 19459

Answers (4)

Coffee
Coffee

Reputation: 1771

null(A) will give you the direct answer. If you need a nontrivial solution, try reduced row echelon form and refer the first page of the pdf.

R = rref(A)

http://www.math.colostate.edu/~gerhard/M345/CHP/ch7_4.pdf

Upvotes: 0

duffymo
duffymo

Reputation: 308733

You can see if MATLAB has a singular value decomposition in its toolbox. That will give you the null space of the vector.

Upvotes: 1

Jacob
Jacob

Reputation: 34601

Please note that null(A) does the same thing (for a rank-deficient matrix) as the following, but this is using the svd(A) function in MATLAB (which as I've mentioned in my comments is what null(A) does).

[U S V] = svd(A);
x = V(:,end)

For more about this, here's an link related to this (can't post it to here due to the formulae).

If you want a more intuitive feel of singular and eigenvalue decompositions check out eigshow in MATLAB.

Upvotes: 14

Peter
Peter

Reputation: 132157

You can use N = null(A) to get a matrix N. Any of the columns of N (or, indeed, any linear combination of columns of N) will satisfy Ax = 0. This describes all possible such x - you've just found an orthogonal basis for the nullspace of A.

Note: you can only find such an x if A has non-trivial nullspace. This will occur if rank(A) < #cols of A.

Upvotes: 10

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