CODEWITHSUNDEEP
djangodjango-modelsdjango-templates
klebe85
klebe85

Reputation: 286

Show possible choices of a model field in a template

In my exercise I have a Django model of a book, having a field "genre". This field has the following option choices

GENRES_CHOICE = (
                 ('ADV','Adventure'),
                 ('FAN','Fantasy'),
                 ('POE','Poetry'),
                )

and the model field is 

 genre = models.CharField(max_length = 3, blank = False, choices = GENRES_CHOICE, db_index = True, editable = False)

In my template I would like to show to the user the list of the genres (Adventure, Fantasy, Poetry) and hava available the keys, in order to possibly use them as parameters.

In order to do so, I would like to have a function that returns the data structure GENRES_CHOICE, but I am not able to. How to solve this problem?

EDIT: more code details

appname= mybookshelf, file -> models/Book.py

# possible choices for the gerne field
GENRES_CHOICE = (
                  ('ADV','Adventure'),
                  ('FAN','Fantasy'),
                  ('POE','Poetry'),
                )

class Book(models.Model):
    """
    This is the book model

   ...

 ## ATTRIBUTES (better use init, but in Django not always possible)
    id = models.CharField(max_length = 64, blank = False, unique = True, primary_key = True,   editable = False)
    """ unique id for the element """

        genre = models.CharField(max_length = 3, blank = False, choices = GENRES_CHOICE, db_index = True, editable = False)
    """ book genre """

    published_date = models.DateField(null = True, auto_now_add = True, editable = False)
    """ date of publishing """

Then, into another file, lets say MyFunctions.py I have 

from mybookshelf.models import GENRES_CHOICE 

    def getBookCategories():
        """
        This function returns the possible book categories 

        categories = GENRES_CHOICE 

        return categories

Upvotes: 0

Views: 377

Answers (3)

phreeLynx
phreeLynx

Reputation: 75

You could use the get_modelfield_display() method in your template, e.g.:

{{ book.get_genre_display }}

Upvotes: 0

Nuno_147
Nuno_147

Reputation: 2913

I am not 100% sure this is what you are after, but if you want to show the user the list of GENRES_CHOICE you can do this in your templete:

{% for choice_id, choice_label in genres %}
           <p> {{ choice_id }} - {{ choice_label }}   </p>        
{% endfor %}

ofcourse pass GENRES_CHOICE as genres

Upvotes: 0

catherine
catherine

Reputation: 22808

views.py

from app_name.models import GENRES_CHOICE

def view_name(request):
    ...............

    return render(request, 'page.html', {
        'genres': GENRES_CHOICE
    })

page.html

{% for genre in genres %}
    {{genre.1}}<br/>
{% endfor %}

Upvotes: 3

Related Questions