Reputation: 203
so i have this 4 tables.
basically i have this code.
$sql_exp = "SELECT c.Branch
FROM dbo.users a
INNER JOIN dbo.FA_Laptop b
ON a.userID = b.UserID
INNER JOIN dbo.Branch c
ON a.BranchID = c.BranchID
WHERE b.fa_id = $faidf";
$rs = $conn->Execute($sql_exp);
if ($rs->EOF) {
echo "<br><br><tr><td><font size=2> Branch is missing</td>";
} else {
while (!$rs->EOF){
echo "<br><br><tr><td>".$rs->Fields("Branch")."</td>";
$rs->movenext();
}
}
$rs->Close();
its my select statement where it enables me to print the "Branch" of the user(juan) where fa_id= $faidf.(for this example $faidf="1")
what i wanted to do next is to print the branch of Pedro by using the FAID=$faidf(which is "1"). though their fa_id is different could i connect it using laptop_id?
Upvotes: 0
Views: 195
Reputation: 1302
Try this SQL
SELECT c.Branchname, a.employeename
FROM dbo.users a
INNER JOIN dbo.FA_Laptop b
ON a.userID = b.UserID
INNER JOIN dbo.Branch c
ON a.BranchID = c.BranchID
WHERE b.Laptop_id=
(SELECT x.laptop_id FROM FA_Laptop x
WHERE x.fa_id="$faidf");
You should get
branchname , employeename
1, juan
1, Pedro
Is that what you were looking for?
Upvotes: 1