CODEWITHSUNDEEP
c++mathoverloading
gen
gen

Reputation: 10030

problems with cmath overloaded functions C++

I need to use cmath's abs() function, but Visual Studio says it's overloaded and I can't even use something like this:

unsigned a = 5, b = 10, c;
c = abs(a-b);

I don't know how to use it properly.

Upvotes: 2

Views: 624

Answers (3)

Open AI - Opting Out
Open AI - Opting Out

Reputation: 24133

You can use the ternary operator:

c = (a > b) ? a - b : b - a;

Upvotes: 0

juanchopanza
juanchopanza

Reputation: 227370

The versions in <cmath> are for floating point types, so there is no unambiguously best match. The overload for integral types are in <cstdlib>, so one of those will yield a good match. If you are using abs on different types, you can use both includes and let overload resolution do its work.

#include <cmath>
#include <cstdlib>
#include <iostream>

int main()
{
  unsigned int a = 5, b = 10, c;
  c = std::abs(a-b);      
  std::cout << c << "\n"; // Ooops! Probably not what we expected.
}

On the other hand, this doesn't yield correct code, since the expression a-b does not invoke integer promotion, so the result is an unsigned int. The real solution is to use signed integral types for differences, as well as the integral type std::abs overloads.

Upvotes: 5

TianyuZhu
TianyuZhu

Reputation: 842

As you can see here, there is no cmath function abs that takes an unsigned integer. This is because unsigned integers are never negative. Try doing the following instead:

int a = 5, b = 10;
int c = abs(a-b);

In this case, c = 5 as expected.

Upvotes: 2

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