CODEWITHSUNDEEP
javaxml
Charles
Charles

Reputation: 11786

org.w3c.dom.Element get position in parent

How to get the position of an Element in the childNode list?

e.g.

<a>
  <b></b><!-- return 0 -->
  <c></c><!-- return 1 -->
</a>

Upvotes: 0

Views: 2363

Answers (2)

Ian Roberts
Ian Roberts

Reputation: 122404

I don't think there's a straightforward way other than to repeatedly call getPreviousSibling() until it returns null or iterate through the parent node's child list until you find one that is == to the node you started with.

As an aside, in the document you give in the question the b element is index 1 in its parent's list of children, and the c element is index 3, because there are whitespace-only text nodes in between (one between the opening a and opening b and another between the closing b and opening c).

Upvotes: 0

T.J. Crowder
T.J. Crowder

Reputation: 1075159

I don't think Element, Node, or NodeList provide a direct way to get this info, but it's easy enough to write your own quick function to do it:

int indexOfNode(Node node) {
    int index;
    Node sibling;

    index = 0;
    while ((sibling = node.getPreviousSibling()) != null) {
        node = sibling;
        ++index;
    }

    return index;
}

Upvotes: 4

Related Questions